What is the sum from n=1 to infinity of 9/(6+9^n) ?

The sum from n=1 to infinity of 9/(6+9^n) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

sum from n=1 to infinity of 9/(6+9^n)

n = 1 \sum \infty \frac{9}{6 + 9 ^{n}}

converges

Solution steps

n = 1 \sum \infty \frac{9}{6 + 9 ^{n}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 9 \cdot n = 1 \sum \infty \frac{1}{6 + 9 ^{n}}

Apply Series Ratio Test:

converges

= 9 converges

= converges

What is the sum from n=1 to infinity of 9/(6+9^n) ?
The sum from n=1 to infinity of 9/(6+9^n) is converges