d/(dθ)(16sin(θ))

解答

\frac{d}{d θ} (16 sin (θ))

16 cos (θ)

求解步骤

\frac{d}{d θ} (16 sin (θ))

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= 16 \frac{d}{d θ} (sin (θ))

使用常见微分定则:

\frac{d}{d θ} (sin (θ)) = cos (θ)

= 16 cos (θ)

\frac{d}{d x} (\frac{1}{5 x + 2})

d er i v a t i v e (ln (3 x))^{2}

\int_{- 1}^{3} x^{3} + 2 x - 5 d x

\frac{\partial}{\partial x} (1 x + 14 y)

\frac{d}{d x} (2 + x^{4})