(dy)/(dx)=x^3+x^2-5x+11

Lösung

\frac{d y}{d x} = x^{3} + x^{2} - 5 x + 11

y = \frac{x ^{4}}{4} + \frac{x ^{3}}{3} - \frac{5 x ^{2}}{2} + 11 x + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = x^{3} + x^{2} - 5 x + 11

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = x^{3} + x^{2} - 5 x + 11

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int x^{3} + x^{2} - 5 x + 11 d x

\int x^{3} + x^{2} - 5 x + 11 d x = \frac{x ^{4}}{4} + \frac{x ^{3}}{3} - \frac{5 x ^{2}}{2} + 11 x + c_{1}

y = \frac{x ^{4}}{4} + \frac{x ^{3}}{3} - \frac{5 x ^{2}}{2} + 11 x + c_{1}

\int_{1}^{1000} \frac{21}{x ^{3}} d x

y^{^{''}} - 2 y^{^{'}} + 5 y = e^{t} cos (2 t)

l a pl a ce t r an s f or m (sin (6 t) - 7)^{2}

\int \frac{cos ^{2} ( θ )}{sin ( θ )} d θ

d er i v a t i v e f (x) = 2^{90}