What is the tangent of y=3-2x^2,(-4,-29) ?

The tangent of y=3-2x^2,(-4,-29) is y=16x+35

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tangent of y=3-2x^2,(-4,-29)

tangent of

y = 3 - 2 x^{2}, (- 4, - 29)

y = 16 x + 35

Solution steps

Find the slope of

y = 3 - 2 x^{2} : \frac{d y}{d x} = - 4 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 16

Find the line with slope m=

16

and passing through

(- 4, - 29) : y = 16 x + 35

y = 16 x + 35

What is the tangent of y=3-2x^2,(-4,-29) ?
The tangent of y=3-2x^2,(-4,-29) is y=16x+35