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Beliebt Rechnen >

integral of (sqrt(x+1))/(sqrt(x+1)+1)

Lösung

\int \frac{x + 1}{x + 1 + 1} d x

Lösung

x + 2 ln x + 1 + 1 - 2 x + 1 - 2 + C

Schritte zur Lösung

\int \frac{x + 1}{x + 1 + 1} d x

Wende U-Substitution an

= \int \frac{2 ( u ^{2} - 2 u + 1 )}{u} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{u ^{2} - 2 u + 1}{u} d u

Multipliziere aus

\frac{u ^{2} - 2 u + 1}{u} : u - 2 + \frac{1}{u}

= 2 \cdot \int u - 2 + \frac{1}{u} d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (\int u d u - \int 2 d u + \int \frac{1}{u} d u)

\int u d u = \frac{u ^{2}}{2}

\int 2 d u = 2 u

\int \frac{1}{u} d u = ln ∣ u ∣

= 2 (\frac{u ^{2}}{2} - 2 u + ln ∣ u ∣)

Setze in

u = x + 1 + 1

ein

= 2 (\frac{( x + 1 + 1 ) ^{2}}{2} - 2 (x + 1 + 1) + ln x + 1 + 1)

Vereinfache

2 (\frac{( x + 1 + 1 ) ^{2}}{2} - 2 (x + 1 + 1) + ln x + 1 + 1) : x + 2 ln x + 1 + 1 - 2 x + 1 - 2

= x + 2 ln x + 1 + 1 - 2 x + 1 - 2

Füge eine Konstante zur Lösung hinzu

= x + 2 ln x + 1 + 1 - 2 x + 1 - 2 + C

Graph

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