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Beliebt Rechnen >

integral of 1/((x+1)^2(x^2+1)^2)

Lösung

\int \frac{1}{( x + 1 ) ^{2} ( x ^{2} + 1 ) ^{2}} d x

Lösung

\frac{1}{2} ln ∣ x + 1 ∣ - \frac{1}{4 ( x + 1 )} + \frac{1}{4} (- ln x^{2} + 1 + arctan (x)) + \frac{1}{4 ( x ^{2} + 1 )} + C

Schritte zur Lösung

\int \frac{1}{( x + 1 ) ^{2} ( x ^{2} + 1 ) ^{2}} d x

Ermittle den Partialbruch von

\frac{1}{( x + 1 ) ^{2} ( x ^{2} + 1 ) ^{2}} : \frac{1}{2 ( x + 1 )} + \frac{1}{4 ( x + 1 ) ^{2}} + \frac{- 2 x + 1}{4 ( x ^{2} + 1 )} - \frac{x}{2 ( x ^{2} + 1 ) ^{2}}

= \int \frac{1}{2 ( x + 1 )} + \frac{1}{4 ( x + 1 ) ^{2}} + \frac{- 2 x + 1}{4 ( x ^{2} + 1 )} - \frac{x}{2 ( x ^{2} + 1 ) ^{2}} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{2 ( x + 1 )} d x + \int \frac{1}{4 ( x + 1 ) ^{2}} d x + \int \frac{- 2 x + 1}{4 ( x ^{2} + 1 )} d x - \int \frac{x}{2 ( x ^{2} + 1 ) ^{2}} d x

\int \frac{1}{2 ( x + 1 )} d x = \frac{1}{2} ln ∣ x + 1 ∣

\int \frac{1}{4 ( x + 1 ) ^{2}} d x = - \frac{1}{4 ( x + 1 )}

\int \frac{- 2 x + 1}{4 ( x ^{2} + 1 )} d x = \frac{1}{4} (- ln x^{2} + 1 + arctan (x))

\int \frac{x}{2 ( x ^{2} + 1 ) ^{2}} d x = - \frac{1}{4 ( x ^{2} + 1 )}

= \frac{1}{2} ln ∣ x + 1 ∣ - \frac{1}{4 ( x + 1 )} + \frac{1}{4} (- ln x^{2} + 1 + arctan (x)) - (- \frac{1}{4 ( x ^{2} + 1 )})

Vereinfache

= \frac{1}{2} ln ∣ x + 1 ∣ - \frac{1}{4 ( x + 1 )} + \frac{1}{4} (- ln x^{2} + 1 + arctan (x)) + \frac{1}{4 ( x ^{2} + 1 )}

Füge eine Konstante zur Lösung hinzu

= \frac{1}{2} ln ∣ x + 1 ∣ - \frac{1}{4 ( x + 1 )} + \frac{1}{4} (- ln x^{2} + 1 + arctan (x)) + \frac{1}{4 ( x ^{2} + 1 )} + C

Graph

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