integral from 0 to 1 of (7x+sqrt(x))

Lösung

\int_{0}^{1} (7 x + x) d x

\frac{25}{6}

Dezimale

4.16666 \dots

Schritte zur Lösung

\int_{0}^{1} 7 x + x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 7 x d x + \int_{0}^{1} x d x

\int_{0}^{1} 7 x d x = \frac{7}{2}

\int_{0}^{1} x d x = \frac{2}{3}

= \frac{7}{2} + \frac{2}{3}

Vereinfache

\frac{7}{2} + \frac{2}{3} : \frac{25}{6}

= \frac{25}{6}

d er i v a t i v e f (x) = x^{5} + 5^{x}

d er i v a t i v e f (x) = - 4 6 x^{2} - 5 x + 10

x \to 0 lim (3 - x)

\frac{\partial}{\partial θ} (a cos (θ))

\frac{\partial}{\partial x} (5 x^{2} y + 6 x y^{3})