integral from 0 to 4 of 3t-7

Lösung

\int_{0}^{4} 3 t - 7 d t

- 4

Schritte zur Lösung

\int_{0}^{4} 3 t - 7 d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 3 t d t - \int_{0}^{4} 7 d t

\int_{0}^{4} 3 t d t = 24

\int_{0}^{4} 7 d t = 28

= 24 - 28

Vereinfache

= - 4

\int_{0}^{1} 3 x - 3 x^{2} d x

\int_{0}^{4} 2 x e^{x^{2}} d x

\int_{- x}^{x} e^{- u^{2}} d u

\int_{\frac{π}{6}}^{π} ∣ cos (x) ∣ d x

\int_{1}^{3} (3 x + 1) d x