integral from 0 to pi of (2x-sin(x))

Lösung

\int_{0}^{π} (2 x - sin (x)) d x

π^{2} - 2

Dezimale

7.86960 \dots

Schritte zur Lösung

\int_{0}^{π} 2 x - sin (x) d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} 2 x d x - \int_{0}^{π} sin (x) d x

\int_{0}^{π} 2 x d x = π^{2}

\int_{0}^{π} sin (x) d x = 2

= π^{2} - 2