integral from 0 to 4 of x-3

Lösung

\int_{0}^{4} x - 3 d x

- 4

Schritte zur Lösung

\int_{0}^{4} x - 3 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} x d x - \int_{0}^{4} 3 d x

\int_{0}^{4} x d x = 8

\int_{0}^{4} 3 d x = 12

= 8 - 12

Vereinfache

= - 4

\int_{1}^{3} (- x^{3} + 4 x^{2} - 3) d x

\int_{7}^{x} sin (t^{4}) d t

\int_{0}^{3} \frac{x ^{3}}{9} d x

\int_{0}^{2} (2 - x^{2}) d x

\int_{1}^{2} x (x^{2} - 1)^{3} d x