integral from 1 to 2 of 2-t

解

\int_{1}^{2} 2 - t d t

\frac{1}{2}

十進法表記

0.5

解答ステップ

\int_{1}^{2} 2 - t d t

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 2 d t - \int_{1}^{2} t d t

\int_{1}^{2} 2 d t = 2

\int_{1}^{2} t d t = \frac{3}{2}

= 2 - \frac{3}{2}

簡素化

2 - \frac{3}{2} : \frac{1}{2}

= \frac{1}{2}