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Beliebt Rechnen >

y^{''}-y^'+y=e^{2t}

Lösung

y^{^{''}} - y^{^{'}} + y = e^{2 t}

Lösung

y = e^{\frac{t}{2}} (c_{1} cos (\frac{3 t}{2}) + c_{2} sin (\frac{3 t}{2})) + \frac{1}{3} e^{2 t}

Schritte zur Lösung

y^{''} (t) - y^{'} (t) + y = e^{2 t}

Solve linear ODE:

y = e^{\frac{t}{2}} (c_{1} cos (\frac{3 t}{2}) + c_{2} sin (\frac{3 t}{2})) + \frac{1}{3} e^{2 t}

y = e^{\frac{t}{2}} (c_{1} cos (\frac{3 t}{2}) + c_{2} sin (\frac{3 t}{2})) + \frac{1}{3} e^{2 t}

Graph

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