fläche x=((y-4)^2)/4 ,y=7-x

Lösung

fläche

x = \frac{( y - 4 ) ^{2}}{4}, y = 7 - x

\frac{64}{3}

Dezimale

21.33333 \dots

Schritte zur Lösung

Stelle

y

nach

x = \frac{( y - 4 ) ^{2}}{4}

um:

y = 2 x + 4, y = - 2 x + 4

f_{1} (x) = 2 x + 4

f_{2} (x) = - 2 x + 4

Um die Schnittpunkte zu finden, löse

f_{i} (x) = f_{j} (x)

2 x + 4 = - 2 x + 4 : x = 0

2 x + 4 = 7 - x : x = 1

- 2 x + 4 = 7 - x : x = 9

= \int_{0}^{1} ∣ f_{1} (x) - f_{2} (x) ∣ d x + \int_{1}^{9} ∣ f_{2} (x) - f_{3} (x) ∣ d x

= \int_{0}^{1} 2 x + 4 - (- 2 x + 4) d x + \int_{1}^{9} - 2 x + 4 - (7 - x) d x

\int_{0}^{1} 2 x + 4 - (- 2 x + 4) d x = \frac{8}{3}

\int_{1}^{9} - 2 x + 4 - (7 - x) d x = \frac{56}{3}

= \frac{8}{3} + \frac{56}{3}

Vereinfache

= \frac{64}{3}

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