derivative y=10000+30xe^{x/(800)}

Lösung

ableitung von

y = 10000 + 30 x e^{\frac{x}{800}}

30 (\frac{e ^{\frac{x}{800}} x}{800} + e^{\frac{x}{800}})

Schritte zur Lösung

\frac{d}{d x} (10000 + 30 x e^{\frac{x}{800}})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (10000) + \frac{d}{d x} (30 x e^{\frac{x}{800}})

\frac{d}{d x} (10000) = 0

\frac{d}{d x} (30 x e^{\frac{x}{800}}) = 30 (e^{\frac{x}{800}} + \frac{e ^{\frac{x}{800}} x}{800})

= 0 + 30 (e^{\frac{x}{800}} + \frac{e ^{\frac{x}{800}} x}{800})

Vereinfache

= 30 (\frac{e ^{\frac{x}{800}} x}{800} + e^{\frac{x}{800}})

a re a x + 2 y = 2, y - x = 1, 2 x + y = 7

\frac{d}{d x} (\frac{π}{x})

d er i v a t i v e 5 cos (π t)

\frac{d}{d n} (2^{n})

l o n g d i v i s i o n \frac{x - 1}{x + 1}