maclaurin 5e^{-x}

Lösung

maclaurin

5 e^{- x}

5 - 5 x + \frac{5}{2} x^{2} - \frac{5}{6} x^{3} + \frac{5}{24} x^{4} + \dots

Schritte zur Lösung

Apply the Maclaurin Formula

= 5 + \frac{\frac{d}{d x} ( 5 e ^{- x} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( 5 e ^{- x} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( 5 e ^{- x} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 5 + \frac{- 5}{1 !} x + \frac{5}{2 !} x^{2} + \frac{- 5}{3 !} x^{3} + \frac{5}{4 !} x^{4} + \dots

Fasse zusammen

= 5 - 5 x + \frac{5}{2} x^{2} - \frac{5}{6} x^{3} + \frac{5}{24} x^{4} + \dots

\frac{d}{d x} ((sin (x))^{l n (x)})

\frac{\partial}{\partial x} (x^{2} y + 5 y^{3})

\frac{d x}{d t} = 3 t^{2} (x^{2} + 4)

\frac{\partial}{\partial x} (9 \frac{x yz}{x + y + z})

p a r i t y x^{c o s (x)}