derivative of 2x^3-16x^2-2c+4d

解

\frac{d}{d x} (2 x^{3} - 16 x^{2} - 2 c + 4 d)

6 x^{2} - 32 x

解答ステップ

\frac{d}{d x} (2 x^{3} - 16 x^{2} - 2 c + 4 d)

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (16 x^{2}) - \frac{d}{d x} (2 c) + \frac{d}{d x} (4 d)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (16 x^{2}) = 32 x

\frac{d}{d x} (2 c) = 0

\frac{d}{d x} (4 d) = 0

= 6 x^{2} - 32 x - 0 + 0

簡素化

= 6 x^{2} - 32 x