(d^2-2d-3)y=5

Lösung

(d^{2} - 2 d - 3) y = 5

y = c_{1} e^{3 x} + c_{2} e^{- x} - \frac{5}{3}

Schritte zur Lösung

(d^{2} - 2 d - 3) y = 5

Solve linear ODE:

y = c_{1} e^{3 x} + c_{2} e^{- x} - \frac{5}{3}

y = c_{1} e^{3 x} + c_{2} e^{- x} - \frac{5}{3}

(d^{3} - d) \cdot y = x

(d^{2} + 2 d + 3) y = sin (x)

y^{^{'''}} - 3 y^{^{''}} + 4 y^{^{'}} - 2 y = e^{x}

(d^{2} - 1) y = x sin^{3} (x) + cos (x)

(d^{4} + 8 d^{2} + 16) \cdot y = - 2