(d^2+4)y=e^3x

Lösung

(d^{2} + 4) y = e^{3} x

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{e ^{3} x}{4}

Schritte zur Lösung

(d^{2} + 4) y = e^{3} x

Solve linear ODE:

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{e ^{3} x}{4}

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{e ^{3} x}{4}

(d - 1)^{2} \cdot y = sin (x) \cdot x^{2} \cdot e^{x}

(d^{3} + 1) \cdot y = cos (2 x - 1)

y^{^{''}} + y^{^{'}} + y = x^{2} + 3 x

(d^{2} + 9) y = sin^{3} (x)

[d^{2} - d - 12] \cdot y = e^{3 x}