integral of ((4-x))/(sqrt(2-x^2))

解

\int \frac{( 4 - x )}{2 - x ^{2}} d x

4 arcsin (\frac{1}{2} x) + 2 - x^{2} + C

解答ステップ

\int \frac{4 - x}{2 - x ^{2}} d x

拡張

\frac{4 - x}{2 - x ^{2}} : \frac{4}{2 - x ^{2}} - \frac{x}{2 - x ^{2}}

= \int \frac{4}{2 - x ^{2}} - \frac{x}{2 - x ^{2}} d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{4}{2 - x ^{2}} d x - \int \frac{x}{2 - x ^{2}} d x

\int \frac{4}{2 - x ^{2}} d x = 4 arcsin (\frac{1}{2} x)

\int \frac{x}{2 - x ^{2}} d x = - 2 - x^{2}

= 4 arcsin (\frac{1}{2} x) - (- 2 - x^{2})

簡素化

= 4 arcsin (\frac{1}{2} x) + 2 - x^{2}

定数を解答に追加する

= 4 arcsin (\frac{1}{2} x) + 2 - x^{2} + C