derivative 1-(1-0.01x)^3

Lösung

ableitung von

1 - (1 - 0.01 x)^{3}

0.000003 x^{2} - 0.0006 x + 0.03

Schritte zur Lösung

\frac{d}{d x} (1 - (1 - 0.01 x)^{3})

Vereinfache

1 - (1 - 0.01 x)^{3} : 0.000001 x^{3} - 0.0003 x^{2} + 0.03 x

= \frac{d}{d x} (0.000001 x^{3} - 0.0003 x^{2} + 0.03 x)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (0.000001 x^{3}) - \frac{d}{d x} (0.0003 x^{2}) + \frac{d}{d x} (0.03 x)

\frac{d}{d x} (0.000001 x^{3}) = 0.000003 x^{2}

\frac{d}{d x} (0.0003 x^{2}) = 0.0006 x

\frac{d}{d x} (0.03 x) = 0.03

= 0.000003 x^{2} - 0.0006 x + 0.03

n = 1 \sum \infty n^{\frac{3}{4}}

\int 90 x^{2} sin (2 + 6 x^{3}) d x

1 - y^{2} d x - 1 - x^{2} d y = 0

f (x) = cos (\frac{x}{3})

d er i v a t i v e f (x) = x^{7} + 10