derivative of 1/10 (x-60^2+100)

解答

\frac{d}{d x} (\frac{1}{10} (x - 60)^{2} + 100)

\frac{1}{5} (x - 60)

求解步骤

\frac{d}{d x} (\frac{1}{10} (x - 60)^{2} + 100)

化简

\frac{1}{10} (x - 60)^{2} + 100 : \frac{( x - 60 ) ^{2}}{10} + 100

= \frac{d}{d x} (\frac{( x - 60 ) ^{2}}{10} + 100)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{( x - 60 ) ^{2}}{10}) + \frac{d}{d x} (100)

\frac{d}{d x} (\frac{( x - 60 ) ^{2}}{10}) = \frac{1}{5} (x - 60)

\frac{d}{d x} (100) = 0

= \frac{1}{5} (x - 60) + 0

化简

= \frac{1}{5} (x - 60)

t a y l or sin^{2} (x)

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