5yy^'=x,y(5)=2

Lösung

5 y y^{^{'}} = x, y (5) = 2

y = \frac{x ^{2}}{5} - 1

Schritte zur Lösung

5 y y^{'} (x) = x

Solve separable ODE:

y = \frac{x ^{2}}{5} - 1

y = \frac{x ^{2}}{5} - 1

y^{^{'}} = - y \cdot 0.04 + 3.5 \cdot 0.5

5 x^{^{'}} + 7 x = 15

\frac{d y}{d x} = y x^{2} - 1.1 y, y (0) = 1

y^{^{'}} + 2 y = - 4

y^{^{'}} = - \frac{5 x ^{4} - 5}{4 y}