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Beliebt Rechnen >

(x^2+1)y^'=(y^2+1)x

Lösung

(x^{2} + 1) y^{^{'}} = (y^{2} + 1) x

Lösung

y = tan (\frac{1}{2} ln (x^{2} + 1) + c_{1})

Schritte zur Lösung

(x^{2} + 1) y^{'} (x) = (y^{2} + 1) x

Solve separable ODE:

y = tan (\frac{1}{2} ln (x^{2} + 1) + c_{1})

y = tan (\frac{1}{2} ln (x^{2} + 1) + c_{1})

Graph

Beliebte Beispiele

x^'+3/200 x=0.006

x^{^{'}} + \frac{3}{200} x = 0.006

y^2*dx-x*y*dy=x^2*y*dy

y^{2} \cdot d x - x \cdot y \cdot d y = x^{2} \cdot y \cdot d y

(dp)/(dt)=(t*cos(t^2))/(p^2)

\frac{d p}{d t} = \frac{t \cdot cos ( t ^{2} )}{p ^{2}}

(yx^2-4y-x^2+4)dx+dy=0

(y x^{2} - 4 y - x^{2} + 4) d x + d y = 0

(dy}{dx}=\frac{y^2-1)/2

\frac{d y}{d x} = \frac{y ^{2} - 1}{2}