y^'+(4x)/(x^2+2)y=0

Lösung

y^{^{'}} + \frac{4 x}{x ^{2} + 2} y = 0

y = \frac{c _{1}}{x ^{4} + 4 x ^{2} + 4}

Schritte zur Lösung

y^{'} (x) + \frac{4 x}{x ^{2} + 2} y = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{4} + 4 x ^{2} + 4}

y = \frac{c _{1}}{x ^{4} + 4 x ^{2} + 4}

e^{2 x} y^{^{'}} = x (cos (y))^{2}

\frac{d y}{d x} = x (6 - y), y = 0, x = 0

x \cdot y^{^{'}} = 15 \cdot y \cdot x + 11 \cdot x

y^{^{'}} - y - 2 = 0

y^{^{'}} = 2 x y^{2}, y (0) = - \frac{1}{x ^{2} + c}