y^'=((y+13))/(5x+6)

Lösung

y^{^{'}} = \frac{( y + 13 )}{5 x + 6}

y = c_{1} 5 5 x + 6 - 13

Schritte zur Lösung

y^{'} (x) = \frac{( y + 13 )}{5 x + 6}

Solve separable ODE:

y = c_{1} 5 5 x + 6 - 13

y = c_{1} 5 5 x + 6 - 13

\frac{d y}{d x} = 6 x^{6} y - y

(\frac{( x + 1 ) ^{2} + 6}{4 ( x + 1 )}) \frac{d y}{d x} = tan (y)

x^{^{'}} - x = - 1

y^{^{'}} = \frac{cot ^{2} ( x )}{2 y}

\frac{d z}{d t} = 8 t e^{3 z}