y^'+y/x =x^3y

Lösung

y^{^{'}} + \frac{y}{x} = x^{3} y

y = \frac{e ^{\frac{x ^{4} + c _{1}}{4}}}{x}

Schritte zur Lösung

y^{'} (x) + \frac{y}{x} = x^{3} y

Solve separable ODE:

y = \frac{e ^{\frac{x ^{4} + c _{1}}{4}}}{x}

y = \frac{e ^{\frac{x ^{4} + c _{1}}{4}}}{x}

\frac{d P}{d t} = a \cdot P

x^{^{'}} = x^{2} (t^{2} - 1) (t^{2} - 9), x (0) = 1

\frac{d y}{d x} + y = y^{- 2}

2 d y - (y - 7)^{2} d x = 0

\frac{d}{d x} (y^{3}) = 50 x