xy^'-3y+2=0

Lösung

x y^{^{'}} - 3 y + 2 = 0

y = \frac{c _{1} x ^{3}}{3} + \frac{2}{3}

Schritte zur Lösung

x y^{'} (x) - 3 y + 2 = 0

Solve separable ODE:

y = \frac{c _{1} x ^{3}}{3} + \frac{2}{3}

y = \frac{c _{1} x ^{3}}{3} + \frac{2}{3}

\frac{d y}{d x} = 6 y ln (\frac{2}{y})

- \frac{d h}{d t} = 5 h

ln (x) y^{^{'}} - \frac{2 y}{x} = 0

3 e^{7 x} \frac{d y}{d x} = - 49 \frac{x}{y ^{2}}, y (0) = 1

a y d x + x d y = 0