e^{x+2y}-e^{-3y}y^'=0

Lösung

e^{x + 2 y} - e^{- 3 y} y^{^{'}} = 0

y = - \frac{ln ( - 5 e ^{x} - c _{1} )}{5}

Schritte zur Lösung

e^{x + 2 y} - e^{- 3 y} y^{'} (x) = 0

Solve separable ODE:

y = - \frac{ln ( - 5 e ^{x} - c _{1} )}{5}

y = - \frac{ln ( - 5 e ^{x} - c _{1} )}{5}

4 y^{^{'}} = 1 + x + y + x y

y^{^{'}} + 18 y^{^{'}} + 81 y = 0

\frac{d y}{d x} = (- n y)

\frac{d h}{d t} = kh (t)^{n}

x + \frac{y d y}{d x} = 2