(dx)/(dt)x^3+4t^2=65

Lösung

\frac{d x}{d t} x^{3} + 4 t^{2} = 65

x = 4 260 t - \frac{16 t ^{3}}{3} + c_{1}, x = - 4 260 t - \frac{16 t ^{3}}{3} + c_{1}

Schritte zur Lösung

\frac{d x}{d t} x^{3} + 4 t^{2} = 65

Solve separable ODE:

x = 4 260 t - \frac{16 t ^{3}}{3} + c_{1}, x = - 4 260 t - \frac{16 t ^{3}}{3} + c_{1}

x = 4 260 t - \frac{16 t ^{3}}{3} + c_{1}, x = - 4 260 t - \frac{16 t ^{3}}{3} + c_{1}

y^{^{'}} + 4 y^{^{'}} + 3 y = 0

\frac{d y}{d x} sin (y) = 4 x^{4} - 4

y^{^{'}} = 10 x y - 2 x, y (0) = 1

y^{^{'}} = 10 x y - 2 x, y (0) = 3

y^{^{'}} = 10 x y - 2 x, y (0) = 7