y+y^'x=0

Lösung

y + y^{^{'}} x = 0

y = \frac{c _{1}}{x}

Schritte zur Lösung

y + y^{'} (x) x = 0

Solve separable ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

y^{^{'}} = 5 x y^{6}

7 y d y = \frac{3}{x} d x

x^{2} + 6 d x - \frac{1}{x csc ( - 8 y )} d y = 0

y^{^{'}} = \frac{y ( y - 2 )}{x ( y - 1 )}

x \cdot \frac{d x}{d t} = e^{3 x} t