y^{''}+4y=9sec(2x)

Lösung

y^{^{''}} + 4 y = 9 sec (2 x)

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{9}{4} ln (cos (2 x)) cos (2 x) + \frac{9}{2} x sin (2 x)

Schritte zur Lösung

y^{''} (x) + 4 y = 9 sec (2 x)

Solve linear ODE:

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{9}{4} ln (cos (2 x)) cos (2 x) + \frac{9}{2} x sin (2 x)

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{9}{4} ln (cos (2 x)) cos (2 x) + \frac{9}{2} x sin (2 x)

y^{^{''}} + 2 y^{^{'}} + y = x^{2} e - x

(D^{2} + 1) y = csc (x)

y^{^{''}} + 2 y^{^{'}} = 3 e^{- 2 t}

y^{^{''}} - 4 y = e^{x}

y^{^{''}} - 4 y = - 12 e^{- 2 x} + 15 cos (x) + 8 x