derivative of-2sin(2x+2cos(2x))

Lösung

\frac{d}{d x} (- 2 sin (2 x) + 2 cos (2 x))

- 4 cos (2 x) - 4 sin (2 x)

Schritte zur Lösung

\frac{d}{d x} (- 2 sin (2 x) + 2 cos (2 x))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 sin (2 x)) + \frac{d}{d x} (2 cos (2 x))

\frac{d}{d x} (2 sin (2 x)) = 4 cos (2 x)

\frac{d}{d x} (2 cos (2 x)) = - 4 sin (2 x)

= - 4 cos (2 x) - 4 sin (2 x)

d er i v a t i v e \frac{x}{x - 8}

x \to 0 + lim (2 x e^{- 3 x})

\int_{0}^{16} \frac{500 x}{x ^{2} + 24} d x

d er i v a t i v e 5 π x^{2}

\frac{\partial}{\partial x} (40 x^{\frac{3}{4}} y^{\frac{1}{4}})