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Beliebt Rechnen >

y^{''}+2y^'+y=e^{2x}+cos(x)

Lösung

y^{^{''}} + 2 y^{^{'}} + y = e^{2 x} + cos (x)

Lösung

y = c_{1} e^{- x} + c_{2} x e^{- x} + \frac{1}{9} e^{2 x} + \frac{1}{2} sin (x)

Schritte zur Lösung

y^{''} (x) + 2 y^{'} (x) + y = e^{2 x} + cos (x)

Solve linear ODE:

y = c_{1} e^{- x} + c_{2} x e^{- x} + \frac{1}{9} e^{2 x} + \frac{1}{2} sin (x)

y = c_{1} e^{- x} + c_{2} x e^{- x} + \frac{1}{9} e^{2 x} + \frac{1}{2} sin (x)

Graph

Beliebte Beispiele

y^{''}+y-1=0,y(0)=0,y(1)=0

y^{^{''}} + y - 1 = 0, y (0) = 0, y (1) = 0

y^{''}-y^'=4xe^x

y^{^{''}} - y^{^{'}} = 4 x e^{x}

solvefor d,d(q)=(300)/(0.4q+8)

so l v e f or d, d (q) = \frac{300}{0.4 q + 8}

y^{''}+4y^'+3y=1-\H(t-2)+\H(t-6)

y^{^{''}} + 4 y^{^{'}} + 3 y = 1 - H (t - 2) + H (t - 6)

2y^{''}+y^'-3y=e^x-x

2 y^{^{''}} + y^{^{'}} - 3 y = e^{x} - x