y^'=9x+y

Lösung

y^{^{'}} = 9 x + y

y = - 9 (x + 1) + c_{1} e^{x}

Schritte zur Lösung

y^{'} (x) = 9 x + y

Solve linear ODE:

y = - 9 (x + 1) + c_{1} e^{x}

y = - 9 (x + 1) + c_{1} e^{x}

(2 e^{y} - x) (\frac{d y}{d x}) = 1

d er i v a t i v e f (x) = - 7 e^{- 3 x} - 6 e^{- 3 x} x

x \to 3 lim (\frac{x ^{2} - 8}{x - 3})

\frac{d}{d x} (x - 3 x^{2} + 8 x^{- 2})

\frac{d y}{d x} = y + 4 y \cdot cos (2 x)