de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Rechnen >

2y^{''}+18y+5=0,y(0)=0,y^'(0)=0

Lösung

2 y^{^{''}} + 18 y + 5 = 0, y (0) = 0, y^{^{'}} (0) = 0

Lösung

y = \frac{5}{18} cos (3 t) - \frac{5}{18}

Schritte zur Lösung

2 y^{''} (t) + 18 y + 5 = 0

Solve linear ODE:

y = \frac{5}{18} cos (3 t) - \frac{5}{18}

y = \frac{5}{18} cos (3 t) - \frac{5}{18}

Graph

Beliebte Beispiele

solvefor y,(d^3+4d)y=2t+t^2

so l v e f or y, (d^{3} + 4 d) y = 2 t + t^{2}

y^{^{''}} + y = 2 \cdot e^{x}

y^{''}-y^'-6y=10xe^{3x}+17e^{3x}

y^{^{''}} - y^{^{'}} - 6 y = 10 x e^{3 x} + 17 e^{3 x}

y^{''}-4y=x+sin(x)

y^{^{''}} - 4 y = x + sin (x)

y^{''}+2y^'+y=(1/6)(e^{-x})

y^{^{''}} + 2 y^{^{'}} + y = (\frac{1}{6}) (e^{- x})