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Beliebt Rechnen >

y^{''}+2y^'+10y=10x+2

Lösung

y^{^{''}} + 2 y^{^{'}} + 10 y = 10 x + 2

Lösung

y = e^{- x} (c_{1} cos (3 x) + c_{2} sin (3 x)) + x

Schritte zur Lösung

y^{''} (x) + 2 y^{'} (x) + 10 y = 10 x + 2

Solve linear ODE:

y = e^{- x} (c_{1} cos (3 x) + c_{2} sin (3 x)) + x

y = e^{- x} (c_{1} cos (3 x) + c_{2} sin (3 x)) + x

Graph

Beliebte Beispiele

y^{'''}+3y^{''}-7y^'+2y=3x+10sin(x)

y^{^{'''}} + 3 y^{^{''}} - 7 y^{^{'}} + 2 y = 3 x + 10 sin (x)

y^{''}+2y^'+y=(2+1)te^{(-t)}

y^{^{''}} + 2 y^{^{'}} + y = (2 + 1) t e^{(- t)}

y^{''}-4y^'+4y=x^2e^2x-e^2x

y^{^{''}} - 4 y^{^{'}} + 4 y = x^{2} e^{2} x - e^{2} x

(d^2x)/(dt^2)+x=2sin(t)

\frac{d ^{2} x}{d t ^{2}} + x = 2 sin (t)

y^{''}+11y=cos(3t)

y^{^{''}} + 11 y = cos (3 t)