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Beliebt Rechnen >

25y^{''}+4y=0

Lösung

25 y^{^{''}} + 4 y = 0

Lösung

y = c_{1} cos (\frac{2 t}{5}) + c_{2} sin (\frac{2 t}{5})

Schritte zur Lösung

25 y^{''} (t) + 4 y = 0

Solve linear ODE:

y = c_{1} cos (\frac{2 t}{5}) + c_{2} sin (\frac{2 t}{5})

y = c_{1} cos (\frac{2 t}{5}) + c_{2} sin (\frac{2 t}{5})

Graph

Beliebte Beispiele

y^{''}-6y^'+13y=0,y(0)=e^3xcos^2(x)

y^{^{''}} - 6 y^{^{'}} + 13 y = 0, y (0) = e^{3} x cos^{2} (x)

y^{'''}-5y^{''}+y^'-5y=0

y^{^{'''}} - 5 y^{^{''}} + y^{^{'}} - 5 y = 0

66y^{'''}+17y^{''}+y^'=0

66 y^{^{'''}} + 17 y^{^{''}} + y^{^{'}} = 0

y^{'''}-15y^{''}+27y^'+243y=0

y^{^{'''}} - 15 y^{^{''}} + 27 y^{^{'}} + 243 y = 0

2x^{''}+2x^'+3x=0

2 x^{^{''}} + 2 x^{^{'}} + 3 x = 0