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Beliebt Rechnen >

y^{''}+(25/6)y^'+25y=0

Lösung

y^{^{''}} + (\frac{25}{6}) y^{^{'}} + 25 y = 0

Lösung

y = e^{- \frac{25 t}{12}} (c_{1} cos (\frac{5 119 t}{12}) + c_{2} sin (\frac{5 119 t}{12}))

Schritte zur Lösung

y^{''} (t) + (\frac{25}{6}) y^{'} (t) + 25 y = 0

Solve linear ODE:

y = e^{- \frac{25 t}{12}} (c_{1} cos (\frac{5 119 t}{12}) + c_{2} sin (\frac{5 119 t}{12}))

y = e^{- \frac{25 t}{12}} (c_{1} cos (\frac{5 119 t}{12}) + c_{2} sin (\frac{5 119 t}{12}))

Graph

Beliebte Beispiele

(D^{3} - 1) y = 0

28y^{''}+17y^'-3y=0

28 y^{^{''}} + 17 y^{^{'}} - 3 y = 0

x^{''}+6x^'+25x=0,x(0)= 1/2 ,x^'(0)=0

x^{^{''}} + 6 x^{^{'}} + 25 x = 0, x (0) = \frac{1}{2}, x^{^{'}} (0) = 0

81y^{''}-90y^'+106y=0

81 y^{^{''}} - 90 y^{^{'}} + 106 y = 0

y^{''}+4y^'+13y=0,y(0)=4,y^'(0)=-7

y^{^{''}} + 4 y^{^{'}} + 13 y = 0, y (0) = 4, y^{^{'}} (0) = - 7