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Beliebt Rechnen >

9y^{''}+12y^'+29y=0,y(0)=1,y^'(1)=3

Lösung

9 y^{''} + 12 y^{'} + 29 y = 0

Lösung

y = e^{- \frac{2 t}{3}} (c_{1} cos (\frac{5 t}{3}) + c_{2} sin (\frac{5 t}{3}))

Schritte zur Lösung

9 y^{''} (t) + 12 y^{'} (t) + 29 y = 0

Solve linear ODE:

y = e^{- \frac{2 t}{3}} (c_{1} cos (\frac{5 t}{3}) + c_{2} sin (\frac{5 t}{3}))

y = e^{- \frac{2 t}{3}} (c_{1} cos (\frac{5 t}{3}) + c_{2} sin (\frac{5 t}{3}))

Beliebte Beispiele

f^{''}(t)+f(t)=0

f^{^{''}} (t) + f (t) = 0

y^{''}-6y^'=0,y(0)=5-5e^6,y(1)=0

y^{^{''}} - 6 y^{^{'}} = 0, y (0) = 5 - 5 e^{6}, y (1) = 0

y^{''}-8y^'+5y=0

y^{^{''}} - 8 y^{^{'}} + 5 y = 0

1x^{''}+6x^'-1x=0

1 x^{^{''}} + 6 x^{^{'}} - 1 x = 0

6y^{''''}+77y^{''}+25y=0

6 y^{^{''''}} + 77 y^{^{''}} + 25 y = 0