y^'=-4xy^2

Lösung

y^{^{'}} = - 4 x y^{2}

y = - \frac{1}{- 2 x ^{2} + c _{1}}

Schritte zur Lösung

y^{'} (x) = - 4 x y^{2}

Solve separable ODE:

y = - \frac{1}{- 2 x ^{2} + c _{1}}

y = - \frac{1}{- 2 x ^{2} + c _{1}}

(x y + x^{3} y) y^{^{'}} = 1 + y^{2}

y^{^{'}} + sin (x) y = 5 sin (x)

y^{^{'}} = 3 x + e^{x}

y^{^{'}} y e^{- x} = 0

f^{^{''}} (x) = 3 x + 1