y^'ye^{-x}=0

Lösung

y^{^{'}} y e^{- x} = 0

y = c_{1}

Schritte zur Lösung

y^{'} (x) y e^{- x} = 0

Isoliere

y^{'} (x) : y^{'} (x) = 0

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int 0 d x

\int 0 d x = c_{1}

y = c_{1}

f^{^{''}} (x) = 3 x + 1

2 y^{^{'''}} = e^{x} y^{^{'''}}

f^{^{'}} (x) = 4 x + 9

2 y^{^{'}} + y^{3} = 0

2 x^{2} y^{^{'}} = x^{2} + y^{2}