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Beliebt Rechnen >

y^{''}+y^'=sin(t),y(0)=1,y^'(0)=2

Lösung

y^{^{''}} + y^{^{'}} = sin (t), y (0) = 1, y^{^{'}} (0) = 2

Lösung

y = \frac{5}{2} + \frac{3}{2} - \frac{5}{2} e^{- t} + \frac{- cos ( t ) - sin ( t )}{2}

Schritte zur Lösung

y^{''} (t) + y^{'} (t) = sin (t)

Solve linear ODE:

y = \frac{5}{2} + \frac{3}{2} - \frac{5}{2} e^{- t} + \frac{- cos ( t ) - sin ( t )}{2}

y = \frac{5}{2} + \frac{3}{2} - \frac{5}{2} e^{- t} + \frac{- cos ( t ) - sin ( t )}{2}

Graph

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