laplacetransform 2/3 t^3e^{-8t}

Lösung

laplace transformation

\frac{2}{3} t^{3} e^{- 8 t}

\frac{4}{( s + 8 ) ^{4}}

Schritte zur Lösung

L {\frac{2}{3} e^{- 8 t} t^{3}}

Verwende die konstante Multiplikationseigenschaft der Laplace-Transformation:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= \frac{2}{3} L {t^{3} e^{- 8 t}}

L {t^{3} e^{- 8 t}} : \frac{6}{( s + 8 ) ^{4}}

= \frac{2}{3} \cdot \frac{6}{( s + 8 ) ^{4}}

Fasse

\frac{2}{3} \frac{6}{( s + 8 ) ^{4}}

zusammen:

\frac{4}{( s + 8 ) ^{4}}

= \frac{4}{( s + 8 ) ^{4}}

\frac{d}{d x} (3 cos (x) - sin (x))

\int \frac{x + 9}{16 - ( x - 4 ) ^{2}} d x

\int (sin (x))^{11} (cos (x))^{5} d x

y^{^{'}} = y^{3} - 6 x^{2} y^{3}, y (1) = - \frac{1}{2}

x \to 1 lim (\frac{x ^{2} + 1}{x + 1})