d/(dy)(y^y)

Lösung

\frac{d}{d y} (y^{y})

y^{y} (ln (y) + 1)

Schritte zur Lösung

\frac{d}{d y} (y^{y})

Wende Exponentenregel an:

a^{b} = e^{b l n (a)}

y^{y} = e^{y l n (y)}

= \frac{d}{d y} (e^{y l n (y)})

Wende die Kettenregel an:

e^{y l n (y)} \frac{d}{d y} (y ln (y))

= e^{y l n (y)} \frac{d}{d y} (y ln (y))

\frac{d}{d y} (y ln (y)) = ln (y) + 1

= e^{y l n (y)} (ln (y) + 1)

e^{y l n (y)} = y^{y}

= y^{y} (ln (y) + 1)

\frac{d}{d x} (e^{3 x^{2}} + ln (5 x - 4))

\frac{d}{d x} (x - sin^{2} (x) - 4)

\frac{\partial}{\partial x} (e^{- x} cos (- 8 y))

in v erse l a pl a ce \frac{1}{( s ^{2} + 3 s + 2 )}

x \to \infty lim (cos (x))