integral from 0 to 1 of 4sqrt(x)-4x

Lösung

\int_{0}^{1} 4 x - 4 x d x

\frac{2}{3}

Dezimale

0.66666 \dots

Schritte zur Lösung

\int_{0}^{1} 4 x - 4 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 4 x d x - \int_{0}^{1} 4 x d x

\int_{0}^{1} 4 x d x = \frac{8}{3}

\int_{0}^{1} 4 x d x = 2

= \frac{8}{3} - 2

Vereinfache

\frac{8}{3} - 2 : \frac{2}{3}

= \frac{2}{3}

\int \frac{x ^{5}}{( 3 - x ^{6} ) ^{4}} d x

n = 5 \sum \infty \frac{n !}{n ^{n}}

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