de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Rechnen >

inverselaplace s/(s^2+1)

Lösung

inverse laplace transformation

\frac{s}{s ^{2} + 1}

Lösung

cos (t)

Schritte zur Lösung

L^{- 1} {\frac{s}{s ^{2} + 1}}

Wende inverse Transformationsregel an: if

L^{- 1} {F (s)} = f (t)

dann

L^{- 1} {s F (s)} = \frac{d}{d t} f (t) + f (0)

Für

\frac{s}{s ^{2} + 1} : F (s) = \frac{1}{s ^{2} + 1}

= \frac{d}{d t} (L^{- 1} {\frac{1}{s ^{2} + 1}}) + L^{- 1} {\frac{1}{s ^{2} + 1}} (0)

L^{- 1} {\frac{1}{s ^{2} + 1}} : sin (t)

\frac{d}{d t} (sin (t)) = cos (t)

Evaluiere

sin (t)

am Punkt

0 = 0

= cos (t)

Beliebte Beispiele

integral of 1/(sqrt(36-6t^2))

\int \frac{1}{36 - 6 t ^{2}} d t

derivative f(x)=2-x^2

d er i v a t i v e f (x) = 2 - x^{2}

inverselaplace {1/(S^3)}

in v erse l a pl a ce {\frac{1}{S ^{3}}}

integral of In(x)

\int I n (x) d x

taylor ln(1-2x)

t a y l or ln (1 - 2 x)