derivative of cos(kx+b)

解答

\frac{d}{d x} (cos (k x + b))

- sin (k x + b) k

求解步骤

\frac{d}{d x} (cos (k x + b))

使用连锁律:

- sin (k x + b) \frac{d}{d x} (k x + b)

= - sin (k x + b) \frac{d}{d x} (k x + b)

\frac{d}{d x} (k x + b) = k

= - sin (k x + b) k

\frac{d}{d x} (\frac{1}{4} sin^{2} (2 x))

\frac{d y}{d x} = \frac{( y ^{2} + 2 x y )}{x ^{2}}

n = 1 \sum \infty 3 e^{- 5 n}

t an g e n t f (x) = 9 + 4 x^{2} - 2 x^{3}, at x = 2

t an g e n t f (x) = 1 + 4 + x^{2}, at x = 0