extreme f(x)=x^3-3x-1

Lösung

extrempunkte

f (x) = x^{3} - 3 x - 1

Maximum (- 1, 1), Minimum (1, - 3)

Schritte zur Lösung

f^{'} (x) = 3 x^{2} - 3

Intervalle finden:

Ansteigend

: - \infty < x < - 1,

Absteigend

: - 1 < x < 1,

Ansteigend

: 1 < x < \infty

Stecke

x = - 1

x^{3} - 3 x - 1 : 1

Maximum (- 1, 1)

Stecke

x = 1

x^{3} - 3 x - 1 : - 3

Minimum (1, - 3)

Maximum (- 1, 1), Minimum (1, - 3)

e x t re m e f (x, y) = \frac{500}{4 + x ^{2} + y ^{2}}

e x t re m e f (x, y) = 2 y^{2} + 2 x y + x^{2} - 16 x - 20 y

e x t re m e f (x, y) = \frac{1}{x} - \frac{64}{y} + x y

e x t re m e f (x) = x 5 - x

e x t re m e f (x) = cos (3 x) - 2, (0, 2 π)