extreme f(x)=2x^2-3x-1

解答

极值点

f (x) = 2 x^{2} - 3 x - 1

极小值 (\frac{3}{4}, - \frac{17}{8})

求解步骤

f^{'} (x) = 4 x - 3

Find intervals:

递减

: - \infty < x < \frac{3}{4},

递增

: \frac{3}{4} < x < \infty

将

x = \frac{3}{4}

代入

2 x^{2} - 3 x - 1 : - \frac{17}{8}

极小值 (\frac{3}{4}, - \frac{17}{8})

e x t re m e \frac{2 x + 1}{x ^{2} + 2 x - 3}

e x t re m e f (x) = \frac{x ^{2} - 11}{x - 6}

e x t re m e \frac{1}{4} - \frac{3}{2} x

e x t re m e 2 x - 3

e x t re m e f (x) = (\frac{x ^{2}}{x + 1})