What is the extreme f(x)=x^3-12x^2-27x+7 ?

The extreme f(x)=x^3-12x^2-27x+7 is Maximum(-1,21),Minimum(9,-479)

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extreme f(x)=x^3-12x^2-27x+7

extreme points

f (x) = x^{3} - 12 x^{2} - 27 x + 7

Maximum (- 1, 21), Minimum (9, - 479)

Solution steps

f^{'} (x) = 3 x^{2} - 24 x - 27

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 9,

Increasing

: 9 < x < \infty

Plug

x = - 1

into

x^{3} - 12 x^{2} - 27 x + 7 : 21

Maximum (- 1, 21)

Plug

x = 9

into

x^{3} - 12 x^{2} - 27 x + 7 : - 479

Minimum (9, - 479)

Maximum (- 1, 21), Minimum (9, - 479)

What is the extreme f(x)=x^3-12x^2-27x+7 ?
The extreme f(x)=x^3-12x^2-27x+7 is Maximum(-1,21),Minimum(9,-479)